info@urfaculty.com

www.urfaculty.com

Govt. Job/ Sarkari Naukri, NEET, CAT, Bank Exam & Study materials

Wednesday, 22 February 2017

Law of Motion II


Numerical Application

Where,
 is the vector resultant of all the forces acting on the body.


Physical Application

Horizontal Plane
i) Case - 1
Body kept on horizontal plane is at rest.

For vertical direction
N = mg(since body is at rest)

ii) Body kept on horizontal plane is accelerating horizontally under single horizontal force.
For vertical direction
N = mg (since body is at rest)
For horizontal direction
F = ma mg

iii) Body kept on horizontal plane is accelerating horizontally towards right under two horizontal forces.(F1 > F2)
For vertical direction
N = mg (since body is at rest)
For horizontal direction
F1 - F2 = ma

iv) Body kept on horizontal plane is accelerating horizontally under single inclined force
For vertical direction
N + FSinθ = mg (since body is at rest)

For horizontal direction
FCosθ = ma

v) Body kept on horizontal plane is accelerating horizontally towards right under an inclined force and a horizontal force.
For vertical direction
N + FSinθ = mg (since body is at rest)
For horizontal direct
F1Cosθ – F= ma

vi) Body kept on horizontal plane is accelerating horizontally towards right under two inclined forces acting on opposite sides.
For vertical direction
N + F1Sinθ = mg + F2 SinФ
(since body is at rest)

For horizontal direction
F1Cosθ – FCosФ = ma

Click here to view complete Chemistry Free Study Materials and Notes for NEET Preparation

Click here to view complete Physics Free Study Materials and Notes for NEET Preparation

Click here to view complete Biology Free Study Materials and Notes for NEET Preparation

Click here to take NEET online practice tests by UrFaculty.com

No comments:
Write comments

Hey, we've just updated our test package. Check'it out here - https://goo.gl/r7FuPT
Join Youth Apps